C++

为什么不能对 C++ 的语法进行简化?

比如

template<typename T>
void addName(T&& name) {
    names_.push_back(std::forward<T>(name));
}

直接简化成

void <T>addName(T&& name) {
    names_.push_back(forward(name));
}

不好吗?

Colliot9/18/2019, 12:49:35 AM

如果允许

void <T>addName(T&& name) {
    names_.push_back(forward(name));
}

就应该允许

void <T>addName(T&& /*unnamed*/) {
}

而形如A < B > C (D, E)的代码可能产生很大的歧义

crazy95sun9/18/2019, 1:04:59 AM

如果允许

void <T>addName(T&& name) {
    names_.push_back(forward(name));
}

就应该允许

void <T>addName(T&& /*unnamed*/) {
}

而形如A < B > C (D, E)的代码可能产生很大的歧义

——crazy95sun

不成立。现在的语法也有这样的歧义

ice100012/4/2022, 3:38:44 AM

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